If you parse

func f() {
    goto label
label:
}

Then you get a LabeledStmt containing an EmptyStmt, and the EmptyStmt.Semicolon has as its value the offset of the } character, and then EmptyStmt.Semicolon.End() returns that+1, which means that the End is recorded as just beyond the closing brace. If you try to delete the statement from the program using the reported boundaries, you end up deleting the brace.

Full test case:

package main

import (
    "fmt"
    "go/ast"
    "go/parser"
    "go/token"
    "log"
)

func main() {
    fset := token.NewFileSet()
    f, err := parser.ParseFile(fset, "x.go", prog, 0)
    if err != nil {
        log.Fatal(err)
    }
    ast.Inspect(f, func(x ast.Node) bool {
        if x != nil {
            fmt.Printf("%T at %d,%d\n", x, x.Pos(), x.End())
        }
        return true
    })
}

var prog = `package p

func f() {
    goto L
L:
}
`

Prints:

*ast.File at 1,35
*ast.Ident at 9,10
*ast.FuncDecl at 12,35
*ast.Ident at 17,18
*ast.FuncType at 12,20
*ast.FieldList at 18,20
*ast.BlockStmt at 21,35
*ast.BranchStmt at 24,30
*ast.Ident at 29,30
*ast.LabeledStmt at 31,35
*ast.Ident at 31,32
*ast.EmptyStmt at 34,35

You can see that the EmptyStmt has the same end as the BlockStmt (and for that matter the FuncDecl and File).
It should be nested inside those.

I am kind of confused by the definition of EmptyStmt.Semicolon. What is the "preceding semicolon" when there's no semicolon due to semicolon insertion? It's tempting to say it is the \n, but there's not always a \n either.

Just to explore, consider changing var prog to

var prog = `package p;func f(){goto L;L:}`

Then the +1 in Semicolon.End cannot be right, because there is nothing safe to +1 over. Contrast this with:

var prog = `package p;func f(){goto L;L:;}`

It seems like the fix requires an extra field in EmptyStmt to distinguish real semicolons from implicit semicolons.