by Gavin.Bong:

What does 'go version' print?

go version go1.2.1 windows/amd64

What steps reproduce the problem?
If possible, include a link to a program on play.golang.org.

1. This code runs on ubuntu 12.04 http://play.golang.org/p/40d_VGdt3Y
   and demonstrates that both path.Split and path.Base correctly returns
   the filename at the end of the path.

2. The following code (which can only work on windows because only windows has the TEMP
environment variable). I use %TEMP% because it gives a canonical path on windows OS.

import "path"
import "path/filepath"
import "fmt"
import "os"

func main() {
   fmt.Println("%TEMP% = ", os.Getenv("TEMP"))
   filename := os.Getenv("TEMP") + string(os.PathSeparator) + "video.mp4"

   d, f := path.Split(filename)
   base := path.Base(filename)

   fmt.Println("f=", f)
   fmt.Println("d=", d)
   fmt.Println(base)
}

What happened?

The execution produced this output.

1) %TEMP% = C:\Users\gavin\AppData\Local\Temp
2) f=C:\Users\gavin\AppData\Local\Temp\video.mp4
3) d=
4) C:\Users\gavin\AppData\Local\Temp\video.mp4


What should have happened instead?

1) Correct
2) f=video.mp4
3) d=C:\Users\gavin\AppData\Local\Temp
4) video.mp4

Please provide any additional information below.