by vonosmas:

What does 'go version' print?
go version go1.2 darwin/amd64

What steps reproduce the problem?
http://play.golang.org/p/bcm1BeQ9r2
re := regexp.MustCompile("aaa")
fmt.Println(re.FindAllStringIndex("aaaaa", -1))

What happened?
program printed
[[0 3]]

What should have happened instead?
expected output:
[[0 3], [1 4], [2 5]]

Please provide any additional information below.
Even if this behavior is expected (which is somewhat counter-intuitive), it should be
documented at
http://golang.org/pkg/regexp/#Regexp.FindAllStringIndex