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fmt: wrong output for format %g #458

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gopherbot opened this issue Dec 24, 2009 · 2 comments
Closed

fmt: wrong output for format %g #458

gopherbot opened this issue Dec 24, 2009 · 2 comments
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@gopherbot
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by trukenmueller:

package main
import (
        "fmt"
)
func main() {
        var x float64
        x = 1.0/9.0
        fmt.Printf("%g %f\n",x,x)
}


What is the expected output?
0.111111 0.111111

%g should produce a short form (at least not longer than %f)

What do you see instead?
0.1111111111111111 0.111111

What is your $GOOS?  $GOARCH? linux 386


Which revision are you using?  (hg identify)
84e097972fa7 tip
@gopherbot
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Comment 1 by trukenmueller:

fix is submitted for review: http://golang.org/cl/183070

@rsc
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rsc commented Dec 28, 2009

Comment 2:

%g in Go is different from %g in C.
%g in Go means print as many digits as are necessary
for strconv.Atof64 or strconv.Atof32 (depending on
the type being printed) to reconstruct exactly the
same value.
To limit the number of digits (and give up this property)
use a size modifier as in %6g.

Owner changed to r...@golang.org.

Status changed to WorkingAsIntended.

@golang golang locked and limited conversation to collaborators Jun 24, 2016
@rsc rsc removed their assignment Jun 22, 2022
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@rsc @gopherbot