What version of Go are you using (go version)?

$ go version 
go version go1.14.1 windows/amd64

Does this issue reproduce with the latest release?

i have no try, but i can't find this issue on the Issues

What operating system and processor architecture are you using (go env)?

set GO111MODULE=on
set GOARCH=amd64
...
set GOEXE=.exe
set GOFLAGS=
set GOHOSTARCH=amd64
set GOHOSTOS=windows
...

$ go env

What did you do?

i want to use two package with two different flag to meet my need, test as follows:

package pk1

import (
	"flag"
	"fmt"
)

var pk1Flag = flag.String("pk1", "hello pk1", "test")

func init() {
	flag.Parse()
	fmt.Println(*pk1Flag)
}

package pk2

import (
	"flag"
	"fmt"
)

var pk2Flag = flag.String("pk2", "hello pk2", "test")

func init() {
	flag.Parse()
	fmt.Println(*pk2Flag)
}

package main

import (
	_ "flag/pk1"
	_ "flag/pk2"

	"fmt"
)

func main() {
	fmt.Println("main")
}

• when i use: go run ./main.go or go run ./main.go -pk1=hhhhhh; both of them work well

 go run .\main.go
hello pk1
hello pk2
main

go run .\main.go -pk1=hhhhhh
hhhhhh
hello pk2
main

• but when using: go run ./main.go -pk2=hhhh or go run ./main.go -pk1=p1 -pk2=p2; both of them do not work

What did you expect to see?

hello pk1
hhhh
main

or

p1
p2
main

What did you see instead?

flag provided but not defined: -pk2
Usage of ...\exe\main.exe:
  -pk1 string
        test (default "hello pk1")
exit status 2