fmt.Sprintf does not handle percent character like fmt.printf does #39051
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You are calling fmt.Printf, which tries to interpret the % in the string. The string is, in fact, what you expect it to be, but your code is going about printing it in the wrong way: https://play.golang.org/p/eoj7Bc5_MX1 |
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What @acln0 said. But also, you're calling fmt.Errorf with the first argument (the format) having a bogus format with percent signs. Use |
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What version of Go are you using (
go version)?Does this issue reproduce with the latest release?
Yes.
What did you do?
fmt.Sprintf of a variable that contain the "%" character.
Here is a link to play.golang.org reproducing the issue: play.golang.org
What did you expect to see?
Let's say I have a string named str and set to "0%{?dist}".
Such as fmt.Printf, I expect to see something like:
str = "0%{?dist}" sp := fmt.Sprintf("20: %s\n", str) fmt.Printf(sp) -> 20: 0%{?dist}What did you see instead?
Sprintf does not seem to handle "%" character like Printf does.
Indeed, here is what Sprintf returns:
str = "0%{?dist}" sp := fmt.Sprintf("20: %s\n", str) fmt.Printf(sp) -> 20: 0%!{(MISSING)?dist}Errorf function has the same behavior with "%" character than Sprintf, but I guess this is because Errorf uses Sprintf.
Thank you !
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