why use fmt.Println in Read function produce twice output #28263
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It also happen when change stdout to stderr or bytes.Buffer |
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This is working as expected. |
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Thanks |
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Please answer these questions before submitting your issue. Thanks!
What version of Go are you using (
go version)?go version go1.11 linux/amd64
Does this issue reproduce with the latest release?
yes
What operating system and processor architecture are you using (
go env)?GOARCH="amd64"
GOBIN=""
GOCACHE="/home/vagrant/.cache/go-build"
GOEXE=""
GOFLAGS=""
GOHOSTARCH="amd64"
GOHOSTOS="linux"
GOOS="linux"
GOPATH="/vagrant/go"
GOPROXY=""
GORACE=""
GOROOT="/usr/local/go"
GOTMPDIR=""
GOTOOLDIR="/usr/local/go/pkg/tool/linux_amd64"
GCCGO="gccgo"
CC="gcc"
CXX="g++"
CGO_ENABLED="1"
GOMOD=""
CGO_CFLAGS="-g -O2"
CGO_CPPFLAGS=""
CGO_CXXFLAGS="-g -O2"
CGO_FFLAGS="-g -O2"
CGO_LDFLAGS="-g -O2"
PKG_CONFIG="pkg-config"
GOGCCFLAGS="-fPIC -m64 -pthread -fmessage-length=0 -fdebug-prefix-map=/tmp/go-build800851283=/tmp/go-build"
What did you do?
code:
https://play.golang.org/p/BJeMXgI2Kw1
What did you expect to see?
test
azAZLbh penpxrq gur pbqr!
What did you see instead?
test
azAZLbh penpxrq gur pbqr!test
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