spec: For each loop over slice of int64 gets automatically converted to int #20974
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You have a bug in your program. See https://golang.org/ref/spec#For_range For questions about Go, see https://golang.org/wiki/Questions. |
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That is, the first value in a range expression over a slice is the index, not the value. |
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Hmm... That explains it. I still would argue that a for range loop with only one variable of interest should be the object itself and not the index of the list. |
mikioh
changed the title
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Please answer these questions before submitting your issue. Thanks!
What version of Go are you using (
go version)?1.8.3
What operating system and processor architecture are you using (
go env)?GOARCH="amd64"
GOBIN="/home/logrhythm/go/bin"
GOEXE=""
GOHOSTARCH="amd64"
GOHOSTOS="linux"
GOOS="linux"
GOPATH="/home/logrhythm/go"
GORACE=""
GOROOT="/bin/go"
GOTOOLDIR="/bin/go/pkg/tool/linux_amd64"
GCCGO="gccgo"
CC="gcc"
GOGCCFLAGS="-fPIC -m64 -pthread -fmessage-length=0 -fdebug-prefix-map=/tmp/go-build020353338=/tmp/go-build -gno-record-gcc-switches"
CXX="g++"
CGO_ENABLED="1"
PKG_CONFIG="pkg-config"
CGO_CFLAGS="-g -O2"
CGO_CPPFLAGS=""
CGO_CXXFLAGS="-g -O2"
CGO_FFLAGS="-g -O2"
CGO_LDFLAGS="-g -O2"
What did you do?
for each automatically converts the type:
https://play.golang.com/p/VMm13-ykYS
What did you expect to see?
Type preserved. The Go compiler should not assume int64 is unnecessary.
What did you see instead?
Types were converted from int64 to int
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