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For primes which are 3 mod 4, using Tonelli-Shanks is slower
and more complicated than using the identity, a**((p+1)/4) mod p == sqrt(a)
which works whenever a is a quadratic residue in F_p.
For 2^450-2^225-1 and 2^10860-2^5430-1, which are 3 mod 4 (and 7 mod 8,
so that 2 is a quadratic residue):
For primes which are 3 mod 4, using Tonelli-Shanks is slower
and more complicated than using the identity,
a**((p+1)/4) mod p == sqrt(a)
which works whenever
a
is a quadratic residue inF_p
.For 2^450-2^225-1 and 2^10860-2^5430-1, which are 3 mod 4 (and 7 mod 8,
so that 2 is a quadratic residue):
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