code review 810043: GNU/Linux sed requires \? rather than ?. Just use * in...

GNU/Linux sed requires \? rather than ?.  Just use * instead.

[iant, 2010-04-06 14:30:57]

Hello golang-dev@googlegroups.com,

I'd like you to review this change.

[iant, 2010-04-06 14:32:38]

Hello rsc (cc: golang-dev@googlegroups.com),

Please take another look.

[r, 2010-04-06 16:19:34]

LGTM

[rsc, 2010-04-06 17:23:25]

*** Submitted as http://code.google.com/p/go/source/detail?r=ac065925190e ***

GNU/Linux sed requires \? rather than ?.  Just use * instead.

R=rsc, r
CC=golang-dev
http://codereview.appspot.com/810043

Committer: Russ Cox <rsc@golang.org>

[r2, 2010-04-06 17:28:53]

On Apr 6, 2010, at 10:23 AM, rsc@golang.org wrote:

> *** Submitted as
> http://code.google.com/p/go/source/detail?r=ac065925190e ***
>
> GNU/Linux sed requires \? rather than ?.  Just use * instead.

it's simpler yet: GNU/Linux sed does not implement ? or +.

-rob

[rsc, 2010-04-06 17:30:37]

>> GNU/Linux sed requires \? rather than ?.  Just use * instead.
>
> it's simpler yet: GNU/Linux sed does not implement ? or +.

s/GNU.Linux/BSD/

[r2, 2010-04-06 17:31:33]

On Apr 6, 2010, at 10:30 AM, Russ Cox wrote:

>>> GNU/Linux sed requires \? rather than ?.  Just use * instead.
>>
>> it's simpler yet: GNU/Linux sed does not implement ? or +.
>
> s/GNU.Linux/BSD/

oh it just gets better.

-rob

[iant, 2010-04-06 18:43:27]

*** Abandoned ***